[tex].[/tex]
Diketahui suatu fungsi :
f(p) = 2p × 200p + 2p + 2p³ - 20
Ditanya ⬇
f(2) = ...
f(3) = ...
f(4) = ...
f(5) = ...
f(6) = ...
f(7) = ...
f(8) = ...
f(9) = ...
f(10) = ...
f(11) = ...
f(12) = ...
-^-
➩ Diketahui :
[tex]\sf \bf \tt f(p) = 2p × 200p + 2p + 2p³ - 20[/tex]
➩ Ditanya :
f(2) = ...
f(3) = ...
f(4) = ...
f(5) = ...
f(6) = ...
f(7) = ...
f(8) = ...
f(9) = ...
f(10) = ...
f(11) = ...
f(12) = ...
➩ Jawab :
- Menentukan nilai f(p)
[tex]\sf \bf \tt f(p) = 2p × 200p + 2p + 2p³ - 20[/tex]
[tex]\bold{\sf \bf \tt f(p) = 400p² + 2p + 2p³ - 20}[/tex]
- Menentukan nilai f(2)
[tex]\sf \bf \tt f(p) = 400p² + 2p + 2p³ - 20[/tex]
[tex]\sf \bf \tt f(2) = 400(2²) + 2(2) + 2(2³) - 20[/tex]
[tex]\sf \bf \tt f(2) = 400(2 × 2) + 2(2) + 2(2×2×2) - 20[/tex]
[tex]\sf \bf \tt f(2) = 400(4) + 2(2) + 2(2×2×2) - 20[/tex]
[tex]\sf \bf \tt f(2) = 1.600+ 2(2) + 2(2×2×2) - 20[/tex]
[tex]\sf \bf \tt f(2) = 1.600+ 4 + 2(2×2×2) - 20[/tex]
[tex]\sf \bf \tt f(2) = 1.600+ 4 + 2(4×2) - 20[/tex]
[tex]\sf \bf \tt f(2) = 1.600+ 4 + 2(8)- 20[/tex]
[tex]\sf \bf \tt f(2) = 1.600+ 4 + 16- 20[/tex]
[tex]\sf \bf \tt f(2) = 1.604 + 16- 20[/tex]
[tex]\sf \bf \tt f(2) = 1.620- 20[/tex]
[tex]\bold{\underline{\boxed{\pink{\sf \bf \tt f(2) = 1.600}}}}[/tex]
- Menentukan nilai f(3)
[tex]\sf \bf \tt f(p) = 400p² + 2p + 2p³ - 20[/tex]
[tex]\sf \bf \tt f(3) = 400(3²) + 2(3) + 2(3³) - 20[/tex]
[tex]\sf \bf \tt f(3) = 400(3×3) + 2(3) + 2(3×3×3) - 20[/tex]
[tex]\sf \bf \tt f(3) = 400(9) + 2(3) + 2(3×3×3) - 20[/tex]
[tex]\sf \bf \tt f(3) = 3.600+ 2(3) + 2(3×3×3) - 20[/tex]
[tex]\sf \bf \tt f(3) = 3.600+ 6 + 2(3×3×3) - 20[/tex]
[tex]\sf \bf \tt f(3) = 3.600+ 6 + 2(9×3) - 20[/tex]
[tex]\sf \bf \tt f(3) = 3.600+ 6 + 2(27)- 20[/tex]
[tex]\sf \bf \tt f(3) = 3.600+ 6 + 54- 20[/tex]
[tex]\sf \bf \tt f(3) = 3.606 + 54- 20[/tex]
[tex]\sf \bf \tt f(3) = 3.660 - 20[/tex]
[tex]\bold{\underline{\boxed{\pink{\sf \bf \tt f(3) = 3.640}}}}[/tex]
- Menentukan nilai f(4)
[tex]\sf \bf \tt f(p) = 400p² + 2p + 2p³ - 20[/tex]
[tex]\sf \bf \tt f(4) = 400(4²) + 2(4) + 2(4³) - 20[/tex]
[tex]\sf \bf \tt f(4) = 400(4×4) + 2(4) + 2(4×4×4) - 20[/tex]
[tex]\sf \bf \tt f(4) = 400(16) + 2(4) + 2(4×4×4) - 20[/tex]
[tex]\sf \bf \tt f(4) = 6.400+ 2(4) + 2(4×4×4) - 20[/tex]
[tex]\sf \bf \tt f(4) = 6.400+ 8 + 2(4×4×4) - 20[/tex]
[tex]\sf \bf \tt f(4) = 6.400+ 8 + 2(16×4) - 20[/tex]
[tex]\sf \bf \tt f(4) = 6.400+ 8 + 2(64)- 20[/tex]
[tex]\sf \bf \tt f(4) = 6.400+ 8 + 128- 20[/tex]
[tex]\sf \bf \tt f(4) = 6.408+ 128- 20[/tex]
[tex]\sf \bf \tt f(4) = 6.536- 20[/tex]
[tex]\bold{\underline{\boxed{\pink{\sf \bf \tt f(4) = 6.516}}}}[/tex]
- Menentukan nilai f(5)
[tex]\sf \bf \tt f(p) = 400p² + 2p + 2p³ - 20[/tex]
[tex]\sf \bf \tt f(5) = 400(5²) + 2(5) + 2(5³) - 20[/tex]
[tex]\sf \bf \tt f(5) = 400(5×5) + 2(5) + 2(5×5×5) - 20[/tex]
[tex]\sf \bf \tt f(5) = 400(25) + 2(5) + 2(5×5×5) - 20[/tex]
[tex]\sf \bf \tt f(5) = 10.000+ 2(5) + 2(5×5×5) - 20[/tex]
[tex]\sf \bf \tt f(5) = 10.000+ 10 + 2(5×5×5) - 20[/tex]
[tex]\sf \bf \tt f(5) = 10.000+ 10 + 2(25×5) - 20[/tex]
[tex]\sf \bf \tt f(5) = 10.000+ 10 + 2(125)- 20[/tex]
[tex]\sf \bf \tt f(5) = 10.000+ 10 + 250- 20[/tex]
[tex]\sf \bf \tt f(5) = 10.010+ 250- 20[/tex]
[tex]\sf \bf \tt f(5) = 10.260- 20[/tex]
[tex]\bold{\underline{\boxed{\pink{\sf \bf \tt f(5) = 10.240}}}}[/tex]
- Menentukan nilai f(6)
[tex]\sf \bf \tt f(p) = 400p² + 2p + 2p³ - 20[/tex]
[tex]\sf \bf \tt f(6) = 400(6²) + 2(6) + 2(6³) - 20[/tex]
[tex]\sf \bf \tt f(6) = 400(6×6) + 2(6) + 2(6×6×6) - 20[/tex]
[tex]\sf \bf \tt f(6) = 400(36) + 2(6) + 2(6×6×6) - 20[/tex]
[tex]\sf \bf \tt f(6) = 14.400+ 2(6) + 2(6×6×6) - 20[/tex]
[tex]\sf \bf \tt f(6) = 14.400+ 12 + 2(6×6×6) - 20[/tex]
[tex]\sf \bf \tt f(6) = 14.400+ 12 + 2(36×6) - 20[/tex]
[tex]\sf \bf \tt f(6) = 14.400+ 12 + 2(216)- 20[/tex]
[tex]\sf \bf \tt f(6) = 14.400+ 12 + 432- 20[/tex]
[tex]\sf \bf \tt f(6) = 14.412 + 128- 20[/tex]
[tex]\sf \bf \tt f(6) = 14.540 - 20[/tex]
[tex]\bold{\underline{\boxed{\pink{\sf \bf \tt f(6) = 14.520}}}}[/tex]
- Menentukan nilai f(7)
[tex]\sf \bf \tt f(p) = 400p² + 2p + 2p³ - 20[/tex]
[tex]\sf \bf \tt f(7) = 400(7²) + 2(7) + 2(7³) - 20[/tex]
[tex]\sf \bf \tt f(7) = 400(7×7) + 2(7) + 2(7×7×7) - 20[/tex]
[tex]\sf \bf \tt f(7) = 400(49) + 2(7) + 2(7×7×7) - 20[/tex]
[tex]\sf \bf \tt f(7) = 19.600+ 2(7) + 2(7×7×7) - 20[/tex]
[tex]\sf \bf \tt f(7) = 19.600+ 14 + 2(7×7×7) - 20[/tex]
[tex]\sf \bf \tt f(7) = 19.600+ 14 + 2(49×7) - 20[/tex]
[tex]\sf \bf \tt f(7) = 19.600+ 14 + 2(343)- 20[/tex]
[tex]\sf \bf \tt f(7) = 19.600+ 14 + 686- 20[/tex]
[tex]\sf \bf \tt f(7) = 19.614+ 686- 20[/tex]
[tex]\sf \bf \tt f(7) = 20.300 - 20[/tex]
[tex]\bold{\underline{\boxed{\pink{\sf \bf \tt f(7) = 20.280}}}}[/tex]
#BelajarBersamaBrainly
Pembahasan :
Diketahui :
[tex]f(p) = 2p × 200p + 2p + 2p³ - 20[/tex]
Ditanya :
f(2) = ...
f(3) = ...
f(4) = ...
f(5) = ...
f(6) = ...
f(7) = ...
f(8) = ...
f(9) = ...
f(10) = ...
f(11) = ...
f(12) = ...
____________________________
Penyelesaian :
- f(2) =
- f(p) = 2p × 200p + 2p + 2p³ - 20
- f(2) = 2(2) × 200(2) + 2(2) + 2(2³) - 20
- f(2) = ( 2×2 ) × ( 200×2 ) + ( 2×2 ) + ( 2×2×2 ) - 20
- f(2) = 4 × 400 + 4 + ( 4×2 ) - 20
- f(2) = 4 × 400 + 4 + 8 - 20
- f(2) = 1.600 + 4 + 8 - 20
- f(2) = 1.604 + 8 - 20
- f(2) = 1.612 - 20
- [tex]\boxed{\green{f(2) = 1.592}}[/tex]
- f(3) =
- f(p) = 2(3) × 200(3) + 2(3) + 2( 3×3×3 ) - 20
- = 6 × 600 + 6 + 2( 27 ) - 20
- = 3.600 + 6 + 54 - 20
- = 3.606 + 54 - 20
- = 3.660 - 20
- [tex]\boxed{\red{= 3.640}}[/tex]
- f(4) =
- f(p) = 2p × 200p + 2p + 2p³ - 20
- = 2(4) × 200(4) + 2(4) + 2(4×4×4) - 20
- = 8 × 800 + 8 + 128 - 20
- = 6.400 + 8 + 128 - 20
- = 6.408 + 128 - 20
- = 6.536 - 20
- [tex]\boxed{\purple{= 6.516}}[/tex]
- f(5) =
- f(p) = 2p × 200p + 2p + 2p³ - 20
- = 2(5) × 200(5) + 2(5) + 2(5×5×5 ) - 20
- = 10 × 1.000 + 10 + 250 - 20
- = 10.000 + 10 + 250 - 20
- = 10.010 + 250 - 20
- = 10.260 - 20
- [tex]\boxed{\pink{= 10.240}}[/tex]
- f(6) = ...
- f(p) = 2p × 200p + 2p + 2p³ - 20
- = 2(6) × 200(6) + 2(6) + 2(6×6×6 ) - 20
- = 12 × 3.600 + 12 + 432 - 20
- = 43.212 + 432 - 20
- [tex]\boxed{\orange{= 43.624}}[/tex]
- f(7) = ...
- f(p) = 2p × 200p + 2p + 2p³ - 20
- = 2(7) × 200(7) + 2(7) + 2(7×7×7) - 20
- = 14 × 1.400 + 14 + 686 - 20
- = 19.600 + 14 + 689 - 20
- = 19.614 + 689 - 20
- = 20.303 - 20
- [tex]\boxed{\blue{= 20.283}}[/tex]
- f(8) = ...
- f(p) = 2p × 200p + 2p + 2p³ - 20
- = 2(8) × 200(8) + 2(8) + 2(8×8×8) - 20
- = 16 × 1.600 + 16 + 1.024 - 20
- = 25.600 + 16 + 1.024 - 20
- = 25.616 + 1.024 - 20
- [tex]\boxed{= 26.620}[/tex]
- f(9) = ...
- f(p) = 2p × 200p + 2p + 2p³ - 20
- = 2(9) × 200(9) + 2(9) + 2(9×9×9 ) - 20
- = 18 × 1.800 + 18 + 1.458 - 20
- [tex]\boxed{\red{= 33.856}}[/tex]
- f(10) = ...
- f(p) = 2p × 200p + 2p + 2p³ - 20
- = 2(10) × 200(10) + 2(10) + 2(10×10×10) - 20
- = 20 × 2.000 + 20 + 2.000 - 20
- [tex]\boxed{\purple {= 42.000}}[/tex]
- f(11) = ...
- f(p) = 2p × 200p + 2p + 2p³ - 20
- = 2(11) × 200(11) + 2(11) + 2(11×11×11 ) - 20
- = 22 × 2.200 + 22 + 2.662 - 20
- [tex]\boxed{\pink{= 50.602}}[/tex]
- f(12) = ...
- f(p) = 2p × 200p + 2p + 2p³ - 20
- = 2(12) × 200(12) + 2(12) + 2(12×12×12) - 20
- = 24 × 2.400 + 24 + 3.456 - 20
- [tex]\boxed{\blue{= 60.004} }[/tex]
____________________________
Detail Jawaban
- Mapel : MTK
- Kelas : 6 SD
- Materi : Pertambahan, pengurangan, perkalian, Perpangkatan
- Kode soal : 2
- Kode kategorisasi : 6.2.2
